F(x)=2x^2+3x+3

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Solution for F(x)=2x^2+3x+3 equation: 



(F)=2F^2+3F+3

We move all terms to the left:

(F)-(2F^2+3F+3)=0

We get rid of parentheses

-2F^2+F-3F-3=0

We add all the numbers together, and all the variables

-2F^2-2F-3=0

a = -2; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·(-2)·(-3)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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